DateTime formats for Python3 date strings

Question

I have the following String representing a date time that I need to read into a valid Python3 datetime object. My best attempt so far:

from datetime import datetime

string_date = '2013-04-27T12:27:52.100Z'
in_memory_date = datetime.strptime(created, '???')

I'm struggling with the date format for this string (???). Can anybody point me in the right direction?

that way: [strftime-strptime-behavior](https://docs.python.org/3/library/datetime.html#strftime-strptime-behavior) there a table what %... to put where, simply adjust it to your pattern — Patrick Artner, Jun 25 '18 at 17:50
I couldn't find a dup, but you can simply use `'%Y-%m-%dT%H:%M:%S.%fZ'`. — Mazdak, Jun 25 '18 at 17:53
This is the exact oppisite: how to create a ISO 8601 from datetime - in includes the parseformat string needed:[given-a-datetime-object-how-do-i-get-an-iso-8601-date-in-string-format](https://stackoverflow.com/questions/114983/given-a-datetime-object-how-do-i-get-an-iso-8601-date-in-string-format) — Patrick Artner, Jun 25 '18 at 18:00

score 2 · Accepted Answer · edited Jun 25 '18 at 17:53

2

datetime.datetime.strptime("2013-04-27T12:27:52.100Z", "%Y-%m-%dT%H:%M:%S.%fZ")

edited Jun 25 '18 at 17:53

Mazdak

answered Jun 25 '18 at 17:51

SamAtWork

I am unsure ... normally answers should contain more then one line of code - thats what comments are for ... – Patrick Artner Jun 25 '18 at 17:54

score 0 · Answer 2 · answered Jun 25 '18 at 18:01

0

You can use to_datetime function from pandas. It is simpler.

pd.to_datetime(string_date)
Timestamp('2013-04-27 12:27:52.100000')

answered Jun 25 '18 at 18:01

YOLO

2 Answers2