Format DateTime with PHP

Question

My API outputs the DateTime in the following format: 2018-06-17T09:07:00Z

How do I display this in a more meaningful way, say, 17/06/2018.

I looked at the Manual: http://php.net/manual/en/datetime.formats.date.php however still wasn't able to find a way to achieve this.

$eventStart = "2018-06-17T09:07:00Z";

Possible duplicate of [Convert date format yyyy-mm-dd => dd-mm-yyyy](https://stackoverflow.com/questions/2487921/convert-date-format-yyyy-mm-dd-dd-mm-yyyy) — Dinesh Ghule, Jun 27 '18 at 05:09

score 1 · Accepted Answer · answered Jun 27 '18 at 05:00

1

You can format it like the below code in PHP:

echo date('d/m/Y', strtotime('2018-06-17T09:07:00Z'));

answered Jun 27 '18 at 05:00

Sinto

1

You are welcome. If you need to do more, please look into this link: https://www.w3schools.com/php/func_date_date_format.asp – Sinto Jun 27 '18 at 05:03

score 1 · Answer 2 · answered Jun 27 '18 at 05:00

1

Use Below code.

date('d/m/Y', strtotime('2018-06-17T09:07:00Z'));

answered Jun 27 '18 at 05:00

Gaurav Kandpal

score 1 · Answer 3 · answered Jun 27 '18 at 05:02

1

Use Date Format :

$inputDate = "2018-06-17T09:07:00Z";
echo date('d/m/Y', strtotime($inputDate));

answered Jun 27 '18 at 05:02

Dinesh Ghule

score 1 · Answer 4 · answered Jun 27 '18 at 05:06

1

Convert the string in time and then format the date which you want

$date = '2018-06-17T09:07:00Z';
echo date('d/m/Y', strtotime($date));

answered Jun 27 '18 at 05:06

DsRaj

score 1 · Answer 5 · answered Jun 27 '18 at 05:27

1

Format the date, but first convert the string to time.

echo date('d/m/Y', strtotime($inputDate));

answered Jun 27 '18 at 05:27

huks

5 Answers5