Sorting a List of Tuples where second value is np.float64

Question

I am trying to sort a list of tuples by the the second value but don't know how to.

This is a sample of the list.

[(0, 0.008419530634828806),
 (1, 0.025931516073376813),
 (2, 0.028300978579639452),
 (3, 0.0290595847459555),
 (4, 0.010301903453003166),
 (5, 0.3762918396584051),
 (6, 0.1081064920744848),
 (7, 0.013774706789176786),
 (8, 0.0002836788948967922),
 (9, 0.23690695321179311),
 (10, 0.007678502309668166),
 (11, 0.004393399463184975),
 (12, 0.015535320262138509),
 (13, 0.005949274957664495)]

I know I can extract the second column and use np.sort() but I want to maintain the tuple format so I can have the index value attached to each float. Is there a way to go about doing this?

Taohidul Islam · Accepted Answer · 2018-06-27T15:12:09.117

0

my_list = [(0, 0.008419530634828806),
 (1, 0.025931516073376813),
 (2, 0.028300978579639452),
 (3, 0.0290595847459555),
 (4, 0.010301903453003166),
 (5, 0.3762918396584051),
 (6, 0.1081064920744848),
 (7, 0.013774706789176786),
 (8, 0.0002836788948967922),
 (9, 0.23690695321179311),
 (10, 0.007678502309668166),
 (11, 0.004393399463184975),
 (12, 0.015535320262138509),
 (13, 0.005949274957664495)]

sorted_list = sorted(my_list,key=lambda x:x[1])
print(sorted_list)

edited Jun 27 '18 at 15:12

answered Jun 27 '18 at 14:52

Taohidul Islam

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I get a nonetype error when I try this. Does the fact that the type is a npfloat make a difference? – Ji Pak Jun 27 '18 at 15:11
It shouldn't make the difference. Please have a look to my updated full code – Taohidul Islam Jun 27 '18 at 15:12

Sorting a List of Tuples where second value is np.float64

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