Mongo ObjectIDs not equal to eachother

Question

new Mongo.ObjectID('18986769bd5eaaa42cb565b1') == new Mongo.ObjectID('18986769bd5eaaa42cb565b1')

returns false

new Mongo.ObjectID('18986769bd5eaaa42cb565b1').toString() == new Mongo.ObjectID('18986769bd5eaaa42cb565b1').toString()

returns true

Is this a bug, a feature or do I need to only work with these using valueOf() and convert it back from string when I need to work with the database?

Two separate JavaScript objects are *never* `==` to each other. — Pointy, Jun 27 '18 at 17:07
You should take a look at this question, it might solve yours https://stackoverflow.com/questions/11637353/comparing-mongoose-id-and-strings Basically they say that you need to use the equals method provided by the mongo library you are using — Roger, Jun 27 '18 at 17:09
@Roger, please add your comment as an answer so I can accept it. — Tyler Clendenin, Jul 09 '18 at 15:29

score 5 · Accepted Answer · answered Jul 11 '18 at 05:01

5

You should take a look at this question, it might solve yours. Basically, they say that you need to use the equals method provided by the mongo library you are using

answered Jul 11 '18 at 05:01

Roger

579
4
13

score 1 · Answer 2 · answered Jun 27 '18 at 17:07

This is completely normal as two objects are not equal to each other even if they contain the same information. You need to loop through all the properties and compare them individually.

console.log({} === {});

example

const obj1 = {id: 12345}
const obj2 = {id: 12345}

console.log(obj1 === obj2);

let same = true;
for(const prop in obj1){
  if(obj2.hasOwnProperty(prop) && obj1[prop] !== obj2[prop]){
      same = false;
      break;
  }
}

console.log(same);

score 0 · Answer 3 · answered Jun 27 '18 at 17:29

0

It's because MongoDB is entirely based around JSON, so even if a particular piece of information is itself a string, Mongo still delivers it as a JSON object. Therefore, you need to parse it back into string form so that you can use it somewhere else.

answered Jun 27 '18 at 17:29

Kourosh Taheri-Golvarzi

124
1
5

score -1 · Answer 4 · edited Apr 08 '22 at 16:34

-1

ObjectId("507c7f79bcf86cd7994f6c0e").valueOf() === "507c7f79bcf86cd7994f6c0e" //true

ObjectId("507c7f79bcf86cd7994f6c0e") === "507c7f79bcf86cd7994f6c0e" //false

ObjectId("507c7f79bcf86cd7994f6c0e").valueOf() === ObjectId("507c7f79bcf86cd7994f6c0e").valueOf() //true

edited Apr 08 '22 at 16:34

Mark Kvetny

664
6
19

answered Apr 08 '22 at 10:53

Manish

1
1

Mongo ObjectIDs not equal to eachother

4 Answers4

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