While Loops and condition of it

Question

I don't know why my While loop condition doesn't work. This is my code:

randomNumber = 2
chosenNumber = ""
while chosenNumber != randomNumber:
    chosenNumber = input("Please enter a number: ")

For example, when I enter 2 for chosenNumber, it still loops and asks me to enter a number. But 2 is equal to randomNumber, why doesn't the While loop stop executing?

Because a string, like `"2"` is not equal to a number, like `2`. — khelwood, Jun 27 '18 at 20:57
Possible duplicate of [How can I read inputs as integers?](https://stackoverflow.com/questions/20449427/how-can-i-read-inputs-as-integers) — user3483203, Jun 27 '18 at 20:58

score 0 · Answer 1 · answered Jun 27 '18 at 20:57

0

input returns a string. So convert it to int before comparison

while chosenNumber != randomNumber:
    chosenNumber = input("Please enter a number: ")
    if chosenNumber.isdigit():
        chosenNumber = int(chosenNumber)

answered Jun 27 '18 at 20:57

Sunitha

11,777
2
20
23

Thanks for the fast reply. I'm a beginner and you guys help me a lot. – jan Jun 27 '18 at 21:00

score 0 · Answer 2 · answered Jun 27 '18 at 21:09

0

You can try this.

randomNumber = 2
chosenNumber = float("inf")
while chosenNumber != randomNumber:
    chosenNumber = int(input("Please enter a number: "))

Hope this helps!

answered Jun 27 '18 at 21:09

Parth Sharma

29
6

Yes I did that! Thanksss – jan Jun 27 '18 at 21:11

While Loops and condition of it

2 Answers2