Sort array with numbers

Question

This is array i have:

var myArray = [
  '<@424507945156784498> - 152,800$',
  '<@381223410610501732> - 100$',
  '<@224451506344606852> - 74,424$',
  '<@101441124537903160> - 65,100$'
];

And this what i want:

var newArray = [
  '<@424507945156784498> - 152,800$',
  '<@224451506344606852> - 74,424$',
  '<@101441124537903160> - 65,100$'
  '<@381223410610501732> - 100$',      
];

I tried to use this method - Javascript : natural sort of alphanumerical strings but its sorting by id (<@424507945156784498>) how can i sort by money value?

It's not sorting by id. It's sorting by the whole string because each entry in the array is one value... The SO link you attached strips non numeric characters (essentially) and sorts the array. — Adrian, Jun 29 '18 at 12:54

mplungjan · Answer 1 · 2018-06-29T13:12:38.817

Split and replace - the sort will sort the existing array - if you need to not mutate it, you need to copy it to another array:

var myArray = [
  '<@424507945156784498> - 152,800$',
  '<@381223410610501732> - 100$',
  '<@224451506344606852> - 74,424$',
  '<@101441124537903160> - 65,100$'
];
function toNum(str) {
  return +str.split(" - ")[1]  // get the amount
    .replace(/[^\d]/g,"");     // remove all non-numeric
}
myArray.sort(function(a,b) {
  return toNum(b)-toNum(a);    // numeric sort in situ
});
console.log(myArray)

Hunter McMillen · Answer 2 · 2018-06-29T13:01:59.090

0

Uses the map-sort-map idiom:

map new data to sort by onto the existing element
sort by added data
map to remove the element that was sorted by

var myArray = [
  '<@424507945156784498> - 152,800$',
  '<@381223410610501732> - 100$',
  '<@224451506344606852> - 74,424$',
  '<@101441124537903160> - 65,100$'
];
    
console.log(
  myArray.map(e => [e, e.split(' - ')[1].replace(/[^0-9]/g,'')])
         .sort((a, b) => b[1] - a[1])
         .map(e => e[0])
);

edited Jun 29 '18 at 13:01

answered Jun 29 '18 at 12:59

Hunter McMillen

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@mplungjan I imagine OP can figure out how to assign to a new variable. – Hunter McMillen Jun 29 '18 at 13:01
1

I imagine OP will be confused when he removes the console.log and there is no change – mplungjan Jun 29 '18 at 13:01

score 0 · Answer 3 · answered Jun 29 '18 at 13:02

Try the following expression:

myArray.sort((x,y)=>x.replace(/,/g,"").match(/(\d+)\$/)[1]*1 < y.replace(/,/g,"").match(/(\d+)\$/)[1]*1)

Explanation:

x.replace(/,/g,"").match(/(\d+)\$/)[1]*1

This expression removes the comma and then matches the number followed by a $. This is done for x and y used in the sort method.

var myArray = [
  '<@424507945156784498> - 152,800$',
  '<@381223410610501732> - 100$',
  '<@224451506344606852> - 74,424$',
  '<@101441124537903160> - 65,100$'
];

console.log(myArray.sort((x,y)=>x.replace(/,/g,"").match(/(\d+)\$/)[1]*1 < y.replace(/,/g,"").match(/(\d+)\$/)[1]*1))

score 0 · Accepted Answer · answered Jun 29 '18 at 14:00

Simply, extract the price value and sort by it:

var myArray = [
  '<@424507945156784498> - 152,800$',
  '<@381223410610501732> - 100$',
  '<@224451506344606852> - 74,424$',
  '<@101441124537903160> - 65,100$'
];

var result = myArray.sort((a,b) => {

  var [priceA, priceB] = [a,b].map(i => parseInt(i.split('-')[1].trim().replace(/\D/g,'')))

  return priceB - priceA;

});

console.log(result);

Sort array with numbers

4 Answers4