Define minimum and maximum length

Question

How is possible to define a minimum and maximum length of user login generated by

FFaker::InternetSE.login_user_name

Used gem FFaker

Hitting in the dark. Try `FFaker::InternetSE.login_user_name(8..20)`. Min length: 8 and Max length: 20. — Jagdeep Singh, Jul 03 '18 at 11:46
You can try `FFaker::InternetSE.login_user_name[minimum_length, maximum_length]`. If you need it more than once, you can use a transient. — Sebastián Palma, Jul 03 '18 at 11:46
@JagdeepSingh `FFaker::InternetSE.login_user_name(8..20)` `ArgumentError: wrong number of arguments (given 1, expected 0)` — Jan Krupa, Jul 03 '18 at 11:49
@SebastianPalma `FFaker::InternetSE.login_user_name[8, 20]` => `""` `FFaker::InternetSE.login_user_name[8, 20]` => "dstrm" — Jan Krupa, Jul 03 '18 at 11:50
That's it, you can start from the index zero if you want to "truncate" your string. — Sebastián Palma, Jul 03 '18 at 11:59
@SebastianPalma Well yes, but when it generates a string with length 2 and I need minimum to be 8, then there is nothing to truncate. — Jan Krupa, Jul 03 '18 at 12:01
Possible duplicate of [Specifying minimum length when using FFaker::Internet.user\_name](https://stackoverflow.com/questions/51071115/specifying-minimum-length-when-using-ffakerinternet-user-name) — Greg, Jul 03 '18 at 15:15

score 2 · Accepted Answer · answered Jul 03 '18 at 12:10

You can store the result of FFaker::InternetSE.login_user_name and check if the size of the string generated is between the minimum and maximum length you need, if so, return it, otherwise call the function again:

require 'ffaker'

def login_user_name(min, max)
  raise 'max can not be minor than min' if min > max
  username = FFaker::InternetSE.login_user_name
  username.size.between?(min, max) ? username : login_user_name(min, max)
end

p login_user_name(8, 9) # christian
p login_user_name(9, 8) # `login_user_name': max can not be minor than min (RuntimeError)

Define minimum and maximum length

1 Answers1