how to understand if one date in php is less than another minus one day?

Question

how to understand if one date in php is less than another minus one day? I mean if for example a date is set to "2018/07/03"; how can I understand if a given date is less than "2018/07/02"

date1 : year1/month1/day1 date2: year2/month2/day2

<?php
if ($year1 >= $year2) {
        if ($month1 >= $month2) {
                  if (($day1 - 1) > $day2) {
                      echo 'you could do something..';
                   }
          }
}
?>

the above code fails if forexample $year2 = 2017 and $month2 = 11.. can anybody help me? thanks a lot..

Possible duplicate of [Comparing two dates](https://stackoverflow.com/questions/3847736/comparing-two-dates) — Can O' Spam, Jul 03 '18 at 12:06

score 2 · Answer 1 · answered Jul 03 '18 at 12:27

2

Here, this should work.

$date_to_check = new DateTime($yesterday);
$today = new DateTime();
$time_diff = $today->diff($date_to_check)->d;

if($time_diff > 1) {
echo "This is greater than one day.";
}else{
echo "This is not greater than one day.";

answered Jul 03 '18 at 12:27

tim

677
9
11

score 1 · Accepted Answer · edited Jun 20 '20 at 09:12

$date = strtotime("2018/07/01");
$date2 = strtotime("2018/07/02");

if($date > $date2){
  print('date is bigger');
  // do stuff when date is bigger than date2
} else {
  // else ...
  print('date2 is bigger');
}

To convert string to date php has function named strtotime(). Compairing date objects is simple.

There is full information about strtotime() http://php.net/manual/ru/function.strtotime.php

Another way:

$date = new DateTime("2018/07/01");
$date2 = new DateTime("2018/07/02");


if($date->modify("+1day") > $date2){
  print('date is bigger');
  // do stuff when date is bigger than date2
} else {
  // else ...
  print('date2 is bigger or equal');
}

Notice modify modifies $date object itself.

Read more here http://php.net/manual/en/class.datetime.php

how to understand if one date in php is less than another minus one day?

2 Answers2

Another way: