how to run a servlet application with only localhost:8080 address.that means i dont want to any url patterns

Question

I want to run a basic servlet application using Tomcat server. While trying run application on the server,the URL pattern is localhost:8080/myapplication/login. Is there any way to run the whole application using localhost:8080 only?

possible duplicate of https://stackoverflow.com/questions/1363605/tomcat-base-url-redirection — DanielM, Jul 03 '18 at 16:52

Mark Bramnik · Answer 1 · 2018-07-03T19:00:54.310

1

It depends on how exactly does the application run, in which container, etc.

For example, in Tomcat, by default, the context path (myapplication in the question) is created because of the name of the WAR (myapplication.war)

In order to run without context path at all, rename the war into ROOT.war and deploy

edited Jul 03 '18 at 19:00

answered Jul 03 '18 at 16:47

Mark Bramnik

39,963
4
57
97

score 0 · Answer 2 · answered Jul 03 '18 at 19:06

0

You can Define a context in the <Tomcat>/conf/server.xml file as follows

<Host name="localhost"  appBase="webapps" ...>
      ...
      <Context path="/" docBase="myapplication.war"/>
      ...
</Host>

answered Jul 03 '18 at 19:06

Talha Ahmed Khan

15,043
10
42
49

i tried it,but its not working.application is running at localhost:8080/myapplication – sai kiran Jul 04 '18 at 10:45

how to run a servlet application with only localhost:8080 address.that means i dont want to any url patterns

2 Answers2