How to access java.lang.Object json value in JAVA?

Question

I have this code and System.out.println(tempObj); print this json(I/System.out: {id=830, dish_id=789, dish_size=Small, price=21, weight=350, promo_price=, dishes_num_for_promo=0}), can you please help me how to access these json value in JAVA Android

for(int i=0; i<disSizes.length; i++ ){
        Object tempObj =  disSizes[i];

        System.out.println(disSizes);
        System.out.println(tempObj);

    }

Duplicate of https://stackoverflow.com/questions/5566669/how-to-parse-a-json-object-in-android — TheOni, Jul 08 '18 at 18:06
Directly Print the JSON obj in logcat Log.e(TAG,obj.toString) and see the values. — GOKUL, Jul 08 '18 at 18:15

Barns · Answer 1 · 2018-07-10T15:06:49.307

You can use this code to parse the JSONObject:

private void parseDishData(JSONObject jsonObj){
    try{
        int dishId = jsonObj.optInt("dish_id", -1);
        String disSizes = jsonObj.optString("dish_size", "NA");
        String price = jsonObj.optString("price", "NA");
        Log.e("MyDishData", "dishId = " + dishId + " disSizes = " +  disSizes)
    }
    catch(Exception ex){
        Log.e("ERROR", ex.getMessage());
    }
}

Or if you have a String you can use this code to parse the JSON String:

private void parseDishData(String json){
    try{
        JSONObject jsonObj = new JSONObject(json);
        int dishId = jsonObj.optInt("dish_id", -1);
        String disSizes = jsonObj.optString("dish_size", "NA");
        String price = jsonObj.optString("price", "false");
        Log.e("MyDishData", "dishId = " + dishId + " disSizes = " +  disSizes)
    }
    catch(Exception ex){
        Log.e("ERROR", ex.getMessage());
    }
}

Just pass the parseDishData method the JSON string.

EDIT:
Your error:

E/ERROR: Expected literal value at character 73 of {id=830, dish_id=789, dish_size=Small, price=21, weight=350, promo_price=, dishes_num_for_promo=0

You are getting the above error because there appears to be a problem with the JSON string. The key " promo_price" has no value! "promo_price=,". There should be a value for example: "promo_price=10,".

Getting this error E/ERROR: Expected literal value at character 73 of {id=830, dish_id=789, dish_size=Small, price=21, weight=350, promo_price=, dishes_num_for_promo=0} — Umashankar Saw, Jul 08 '18 at 18:23
@UmashankarSaw :: There appears to be an issue with the JSON string. The key " promo_price" has no value! "promo_price=," — Barns, Jul 08 '18 at 18:45
@UmashankarSaw :: Have you had a chance to look at the explanation of why you are getting the error. If you need any help with that, please let me know. — Barns, Jul 10 '18 at 15:09

score 0 · Answer 2 · answered Jul 08 '18 at 18:08

You can construct a JSONObject by casting the object:

JSONObject json = (JSONObject) tempObj;

Now you can access the properties by using the appropriate getters from the JSONObject class according to the type of data you want to get out of it.

For instance you do:

int id = json.getInt("id");

to obtain the id of the object.

score 0 · Answer 3 · answered Jul 08 '18 at 18:28

0

You will cast Object to JSONObject to extract values from this Json.

JSONObject json = (JSONObject) tempObj;

Then you can parse Json by simple methods like

String promo_price = json.getString("promo_price");

answered Jul 08 '18 at 18:28

Khemraj Sharma

57,232
27
203
212

How is this different from the answer provided by @NiVeR ? – Barns Jul 08 '18 at 18:37

How to access java.lang.Object json value in JAVA?

3 Answers3