5
public class Abc {
    public static void main(String args[]) {
        System.out.println(Abc.method());
    }

    static int method() {
        try {
            throw new Exception();
        }
        catch(Exception e) {
            throw new Exception();
        }
        finally {
            return 4;
        }
    }
}

Why is the return value 4?

hexacyanide
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Chandra Kanth
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    try block is for doing some task, if the task cannot be completed ,vthen throw exception from catch Block. you should not throw exceptions in try. – Dead Programmer Feb 26 '11 at 10:58

5 Answers5

14

That's the way finally works. The snippet

try {
    throw new Exception();
} catch(Exception e) {
    throw new Exception();
}

will complete abruptly, but the finally clause will kick in and when it returns it discards the original reason for completing the statement.

This is explained in section Blocks and Statements in the Java Language Specification. I've highlighted the relevant path in your situation:

A try statement with a finally block is executed by first executing the try block. Then there is a choice:

  • If execution of the try block completes normally, then the finally block is executed, and then there is a choice:
    • ...
  • If execution of the try block completes abruptly because of a throw of a value V, then there is a choice:
    • If the run-time type of V is assignable to the parameter of any catch clause of the try statement, then the first (leftmost) such catch clause is selected. The value V is assigned to the parameter of the selected catch clause, and the Block of that catch clause is executed. Then there is a choice:
      • If the catch block completes normally, then the finally block is executed. Then there is a choice:
        • ...
      • If the catch block completes abruptly for reason R, then the finally block is executed. Then there is a choice:
        • If the finally block completes normally, then the try statement completes abruptly for reason R.
        • If the finally block completes abruptly for reason S, then the try statement completes abruptly for reason S (and reason R is discarded).
    • If the run-time type of V is not assignable to the parameter of any catch clause of the try statement, then the finally block is executed. Then there is a choice:
      • ...
  • If execution of the try block completes abruptly for any other reason R, then the finally block is executed. Then there is a choice:
    • ...
aioobe
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2

You should never return from a finally block. This is very bad practice. See Java try-finally return design question and Does finally always execute in Java?.

Community
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JB Nizet
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1

There are several questions on StakOverflow that explain this.

To make it simple: if you put a return or a throw statement in a finally clause this is the last action of your method. Generally speaking this is a bad practice though.

heapOverflow
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1

Finally will always return 4. The finally block will always execute regardless of any exception that is throw in the try and catch blocks.

mmccomb
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0

The fact that the finally block returns a value causes the thrown exception to be swallowed, so it wont propagate out of the method.

pauljwilliams
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