I have this array :
Array
(
[0] => Array
(
[0] => Array
(
[0] => 10
[id_list] => 1
[id] => 1
)
[1] => Array
(
[0] => 11
[id_list] => 1
[id] => 1
)
[2] => Array
(
[0] => 12
[id_list] => 1
[id] => 1
)
)
[1] => Array
(
[0] => Array
(
[0] => 11
[id_list] => 2
[id] => 2
)
[1] => Array
(
[0] => 12
[id_list] => 2
[id] => 2
)
)
[2] => Array
(
[0] => Array
(
[0] => 13
[id_list] => 4
[id] => 4
)
)
)
and this code (where $dataListe is the result of a fetchAll query) :
$result = [];
foreach($dataListe as $listeDiff){
$result[] = $listeDiff;
}
// $resultUnique = array_unique($result);
echo "<pre>".print_r($result, true)."</pre>";
as you can see, there's some contact similar in my first and my second array (but contact can be the same in the 1st and the 3rd array, is I choose to add my contact in my 3rd array).
I want to remove the duplicate of each element in the general array.
But when I use array unique, I get this result :
Array
(
[0] => Array
(
[0] => Array
(
[0] => 10
[id_list] => 1
[id] => 1
)
[1] => Array
(
[0] => 11
[id_list] => 1
[id] => 1
)
[2] => Array
(
[0] => 12
[id_list] => 1
[id] => 1
)
)
)
Please I need help to only keep 1 item of each array at the end !
EDIT : I have almost the good result with the code below, but the id 12 is missing
$result = [];
foreach($dataListe as $listeDiff){
foreach($listeDiff as $contact){
if(!in_array($contact,$result)){
$result[] = $contact;
}
break;
}
}