Regex: Extract a string pattern from a string

Asked Jul 10 '18 at 18:08

Active Jul 11 '18 at 10:12

Viewed 35 times

Want to extract a pattern "Link":URL from a string. Example:

$str = 'I like dogs and cats. View here "Link":http://www.example.com and here "Link":http://www.example2.com';
if (preg_match_all('/"Link":(.*?)/', $str, $match) >= 1) {
    print_r($match);
}

Need to extract "Link":http://www.example.com and "Link":http://www.example2.com.

What am I doing wrong?

edited Jul 11 '18 at 10:12

asked Jul 10 '18 at 18:08

user1502826

1

Use greedy dot, `'/"Link":(.*)/'` – Wiktor Stribiżew Jul 10 '18 at 18:09
Both `.*?` and `.*` only make sense if there's something to anchor it on both ends. Else matching for non-space characters would be adviseable. – mario Jul 10 '18 at 18:18
@mario, i agree with you, for example `'/"Link":(.*?)$/'` or `'/"Link":(.*)$/'` – wnull Jul 10 '18 at 18:35
My question is clearly not a duplicate to the one suggested. My question is an attempt to apply the knowledge that would however have been gained from the suggested question. Regardless, thanks for the answer. – user1502826 Jul 11 '18 at 09:55
The answer just extracts all the string after that first match not just the match or matches in the string – user1502826 Jul 11 '18 at 10:14
This worked `'/"Link":([a-z:\/\/\.]+)/'` – user1502826 Jul 11 '18 at 11:14

Regex: Extract a string pattern from a string

0 Answers0