Extract code inside shell script functions

Question

I have a file with more than 20-30 functions like below:

abc(){
 # code of abc function
}
efg(){
 # code of efg function
}
hij(){
 # code of efg function
}

I want to use grep/sed or any other text manipulation tools to extract the code present in a particular function.

I tried this: sed -n '/efg/,/\}/p' file.txt

Output:

efg(){
     # code of efg function
}

How do I exclude the first and last line of the output to get the code only. I know it can be removed using sed but I'd prefer it is in the one-liner itself, but can't figure it out myself

you might want to check an awk solution here. https://stackoverflow.com/questions/38972736/how-to-select-lines-between-two-patterns — abhishek phukan, Jul 11 '18 at 08:28
Do you care for comments and blank lines in the code? If not, you could simply do this, for each function: `type func_name | sed 1d`. Use `compgen -A function` to get the list of functions after sourcing your script. — codeforester, Jul 22 '18 at 06:32

David C. Rankin · Answer 1 · 2018-07-11T07:57:50.637

1

With a slight variation and using n and d you can accomplish the task, e.g.

sed -n '/efg/,/[}]/{/efg/{n};/[}]/{d};p}'

Example Use/Output

$ sed -n '/efg/,/[}]/{/efg/{n};/[}]/{d};p}'
 # code of efg function

(note: for multi-line functions only, and you can escape if you prefer, e.g. \} instead of using a character-class [}])

Short Synopsis

-n suppress printing of pattern space
/efg/,/[}]/ for everything between efg and }
{/efg/{n}; if matches efg then next line
/[}]/{d}; if matches } delete
p otherwise print-it

edited Jul 11 '18 at 07:57

answered Jul 11 '18 at 07:52

David C. Rankin

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macos: `sed: 1: "/efg/,/[}]/{/efg/{n};/[ ...": extra characters at the end of n command` – JOhn Sep 26 '19 at 23:12

Extract code inside shell script functions

1 Answers1