Open file with most similar name

Question

I have a directory with files.
I have a function that takes a String fileName. I would like to either be able to open that file and if it does not exist open a file that has the most similar name.
E.g.
If filename passed is file_name_v1.txt then if that does not exist open file_name_v2.txt
These are just examples. I don’t really know know the actual number after _v so I don’t know how I could create a regex for a file for this case

Answer 1

This has been answered here: How to find files that match a wildcard string in Java?

Note that the solutions above requires Java 7 NIO.

PathMatcher pathMatcher = FileSystems.getDefault()
    .getPathMatcher("regex:Test.[\\/]sample\\w+\\.txt");
try (DirectoryStream<Path> dirStream = Files.newDirectoryStream(
        new File("..").toPath(), pathMatcher::matches)) {
    dirStream.forEach(path -> System.out.println(path));
}