What is going on here:
12 % 4 = 0; // integers
(1.2 / 0.1) % 4 = 3; // floats (12) % 4 = 3!
$a = 1.2 / 0.1;
$b = ((int)$a) % 4;
$c = 12 % 4;
print_r([
$a,
$b,
$c,
]);
Asked
Active
Viewed 14 times
0
-
solution is where? – luky Jul 11 '18 at 12:06
-
in the linked duplicate. IEEE 754 floats (used by almost all programming languages) cannot represent all arbitrary precision floating point numbers. This is a tradeoff made for various technical reasons. You are not the first (and won't be the last) to be tripped up by this, canonical example is `0.1 + 0.2 !== 0.3` – Jared Smith Jul 11 '18 at 12:12