numpy fill_between() different diagonal values

Asked Jul 12 '18 at 11:03

Active Jul 12 '18 at 11:07

Viewed 19 times

I have created a 3x3 np.array full of zeros with a = np.zeros((3,3)). I have another 3x1 numpy array b = np.array([[1],[2],[3]]) which values I want to set for the diagonal values in a. Hence I as result I want to have a matrix with the values of b on the diagonal and zeros everywhere else. I tried using the np.fill_diagonal() function with the following code:

a = np.zeros((3,3))
b = np.array([[1],[2],[3]])
print(np.fill_diagonal(a,b))

As result I get:

None

What I am doing wrong and how can I accomplish the above?

edited Jul 12 '18 at 11:07

asked Jul 12 '18 at 11:03

2Obe

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Tried `c = np.fill_diagonal(a,b)` `print(c)` as well as simply `np.fill_diagonal(a,b)` but didn't work at all – 2Obe Jul 12 '18 at 11:08
As written, I tried it but it didnt't work at all. – 2Obe Jul 12 '18 at 11:11
Simply `np.fill_diagonal(a,b)` but this led to a *None* as well – 2Obe Jul 12 '18 at 11:13
No I didn't thanks a lot! Please post it as an answer – 2Obe Jul 12 '18 at 11:18
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you could also multiply your vector by the identity matrix instead of filling a zero matrix, e.g. `a = np.identity(3); b = np.arange(1,4); a * b` to get the same result – Haleemur Ali Jul 12 '18 at 11:22

numpy fill_between() different diagonal values

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