How to do zero padding to a hexadecimal number converted from int?

Asked Jul 18 '18 at 23:49

Active Jul 18 '18 at 23:58

Viewed 38 times

I am printing converted hexadecimal values like the following:

std::cout << std::hex << integers[i] << " "; //i is a loop counter

But it prints out single digits for few values, like FF D2 78 9 A9 87 f ff. I want those single values to have a 0: FF D2 78 09 A9 87 0f ff.

I tried

if(integers[i] == 1 || ... || integers[i] = (int)'f')
{
std::cout << "0" << std::hex << integers[i] << " ";
}

But when 1 ... f is an hexadecimal value it, it does not print properly. How can I convert the value to hex first and check if its one digit or two digits and add 0 padding if it is a single digit?

edited Jul 18 '18 at 23:58

Remy Lebeau

555,201
31
458
770

asked Jul 18 '18 at 23:49

Gravity Mass

2

maybe you want `std::cout << std::hex << std::setw(2) << std::setfill('0') << integers[i] << " ";` ? – M.M Jul 18 '18 at 23:50
Worked perfectly. thanks – Gravity Mass Jul 18 '18 at 23:52
1

@M.M that should be an answer, not a comment – Remy Lebeau Jul 18 '18 at 23:53
1

integers[i] = (int)'f' won't work. – nicomp Jul 18 '18 at 23:54
1

If you are going to test the values manually (which is not needed), you would need something more like this instead `if ((integers[i] >= 0) && (integers[i] < 16)) { std::cout << "0"; } cout << std::hex << integers[i] << " ";` – Remy Lebeau Jul 18 '18 at 23:55
@RemyLebeau I wasn't sure if that was what's being asked – M.M Jul 18 '18 at 23:57

How to do zero padding to a hexadecimal number converted from int?

0 Answers0