In java I can implement in following two ways :
package com.company;
class ToInherit {
public interface MyInterface {
void methodInInterface(boolean isError, String text);
}
}
Main.java
package com.company;
public class Main {
public static void main(String[] args) {
// write your code here
Main mainObj = new Main();
mainObj.MyMethod(new ToInherit.MyInterface() {
@Override
public void methodInInterface(boolean isError, String text) {
// My Task Here
}
});
}
private void MyMethod(ToInherit.MyInterface myInterface) {
myInterface.methodInInterface(true, "Text");
}
}
Main2.java
package com.company;
public class Main2 implements ToInherit.MyInterface {
public static void main(String[] args) {
// write your code here
Main2 main2Obj = new Main2();
main2Obj.MyMethod(main2Obj);
}
@Override
public void methodInInterface(boolean isError, String text) {
// My Task Here
}
private void MyMethod(ToInherit.MyInterface myInterface) {
myInterface.methodInInterface(true, "Text");
}
}
I also know that implementing in C# in this way from Docs - https://learn.microsoft.com/en-us/dotnet/csharp/programming-guide/interfaces/
public class Car : IEquatable<Car>
{
public string Make {get; set;}
public string Model { get; set; }
public string Year { get; set; }
// Implementation of IEquatable<T> interface
public bool Equals(Car car)
{
return this.Make == car.Make &&
this.Model == car.Model &&
this.Year == car.Year;
}
}
But I want to implement it in the way I did in Main.java
I didn't find any way to do in such way in C# without creating an extra method.
