Adding three different char in java as java variable and getting a number

Question

Why i am getting 152, I think it will give me an error. Please explain it.

    public class character {
    public static void main(String[] args) {
        char myCharValue1 = 'A';
        char myCharValue2 = '2';
        char myCharValue3 = '%';

        System.out.println(myCharValue1 + myCharValue2 + myCharValue3);
    }
}

`char` is actually a 16-bit (2 bytes) data-type. Using `+` will cause them to behave like numbers. Use `new String(...);` or `new StringBuilder().append(myCharValue1).append(myCharValue2).append(myCharValue3).toString()`. — Jai, Jul 19 '18 at 08:44

Lino · Accepted Answer · 2018-07-19T08:53:55.767

1

That is because chars refer to a number, which in turn has an ASCII representation.

Looking at an ASCII table you can see that the chars A, 2 and % have following values respectivly: 65, 50 and 37.

Adding those numbers together, you'll end up with 152 which is what you got in your example.

To print out those chars you could use following:

System.out.printf("%s%s%s&n", myCharValue1 + myCharValue2 + myCharValue3);

Which will print A2% (and a newline)

edited Jul 19 '18 at 08:53

answered Jul 19 '18 at 08:44

Lino

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Thank you big bro. I think that's the correct answer. Thank you so much. – Piyush Jul 19 '18 at 08:50

score 0 · Answer 2 · answered Jul 19 '18 at 08:43

0

The concatenation + is for String. What you're doing is adding the numeric values of your chars and printing them together.

If you start with "" and then use + as Patrick Parker shows in his comment, it will become concatenation instead of simple addition and you'll get the result you expect.

answered Jul 19 '18 at 08:43

Kayaman

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Hmm, just try to use it in different way. and Now i get that what is the actual problem. Thank you Kayaman. – Piyush Jul 19 '18 at 08:48

Adding three different char in java as java variable and getting a number

2 Answers2