Python : Can't read '\\' as a string

Question

I wanted to replace a string : 'li\\oa' by 'ext' but I get this error

error: octal escape value \505 outside of range 0-0o377

I know that the problem is: string containing these chracters '\\', so the question is : How can i read these backslashes as a string.

df['col']= df['col'].replace(['li\\oa'],['ext'], regex=True)

Nvm, i found the answer, you need to put '\\\\' backslashes in order for python to consider it as '\\' — Oumab10, Jul 19 '18 at 13:29

score 1 · Accepted Answer · answered Jul 19 '18 at 13:36

1

You have to escape the two backslashes by adding one "\" for each one :

df['col']= df['col'].replace(['li\\\\oa'],['ext'], regex=True)

answered Jul 19 '18 at 13:36

Eduardo Soares

yes thank you, i've already did that – Oumab10 Jul 19 '18 at 13:38
And it has worked? – Eduardo Soares Jul 19 '18 at 13:39
If it worked, please mark the question as solved. – Eduardo Soares Jul 19 '18 at 13:46

score 1 · Answer 2 · answered Jul 19 '18 at 13:36

1

You can declare a string as raw (with an r in front of it) and it will print all its characters:

>>> string = r'li\\oa'
>>> print string
'li\\oa'

answered Jul 19 '18 at 13:36

SaikaVA

I wanted to replace not print – Oumab10 Jul 19 '18 at 13:38
It doesn't have anything to do with print. 'r' will make it to a raw string. – SaikaVA Jul 19 '18 at 13:52

2 Answers2