ordered dictionary python with enumeration

Question

I have created an ordered dictionary in python and enumeration is used for for loop index. It gives following result exactly the way i wanted.

def get_stocks():
    tickers = OrderedDict()
    for ticker in enumerate(sorted(df_symbol.Symbol)):
        tickers[ticker] = "AlphaVantage"
    return tickers

It gets me this which is what I need.

OrderedDict([((0, 'HINDALCO'), 'AlphaVantage'), ((1, 'LUPIN'), 'AlphaVantage'), ((2, 'SUNPHARMA'), 'AlphaVantage')])

Now I want to print something like this from above. I am not successful:

['HINDALCO', 'LUPIN', 'SUNPHARMA']

I am doing something like this:

tickers = get_stocks()
ticker_list = list(tickers.keys())

I am getting:

[(0, 'HINDALCO'), (1, 'LUPIN'), (2, 'SUNPHARMA')]

More precisely:https://stackoverflow.com/a/6455332/3125566 – Moses Koledoye Jul 21 '18 at 10:55 — Moses Koledoye, Jul 21 '18 at 10:55

score 0 · Accepted Answer · answered Jul 21 '18 at 10:52

0

Use a list comprehension.

ticker_list = [name for number, name in get_stocks().keys()]

answered Jul 21 '18 at 10:52

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ordered dictionary python with enumeration

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