shell script expression evaluation into a variable

Question

The below expression

var=$(git log --since='$start_date' --until='$end_date' --author='$commit_author' | grep -i 'merge request\|pull request'  | wc -l)
echo $var

prints var as zero

but if I echo the above expression

git log --since='2018-04-1' --until='2018-06-30' --author='so.sila@xes.com' | grep -i 'merge request\|pull request'  | wc -l

and copy it and execute via terminal works

why is that var not storing the value and returns zero

score 2 · Accepted Answer · answered Jul 21 '18 at 19:05

2

The reason is that '$start_date', '$end_date' etc do not expand to their values as they are in single quotes. Try changing it to double quotes and you may have some luck.

answered Jul 21 '18 at 19:05

Gautam

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shell script expression evaluation into a variable

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