How to generate random increasing or decreasing strings in python?

Question

I need to make sequence of random strings, which increase(decrease) for alphabetic oder. For example: "ajikfk45kJDk", "bFJIPH7CDd", "c".

Your example strings do not strictly increase or decrease in any collating sequence or alphabetical order I know. Please clarify. — Prune, Jul 26 '18 at 22:12
You need to have 26 strings where the first character is the letter of the alphabet respective to its position in the generated sequence, and the remaining characters are random? Why not just generate 26 random strings of `required_length - 1` and prepend the letters of the alphabets to them? — Sean Pianka, Jul 26 '18 at 22:12
Possible duplicate of [Random string generation with upper case letters and digits in Python](https://stackoverflow.com/questions/2257441/random-string-generation-with-upper-case-letters-and-digits-in-python) — joel, Jul 26 '18 at 22:31

score 1 · Answer 1 · answered Jul 26 '18 at 22:37

The simplest thing to do is to create N random strings and then sort them.

So, how do you create a random string? Well, you haven't specified what your rule is, but your three examples are strings of 1 to 12 characters taken from the set of ASCII lowercase, uppercase, and digits, so let's do that.

length = random.randrange(1, 13)
letters = random.choices(string.ascii_letters + string.digits, k=length)
string = ''.join(letters)

So, just do this N times, then sort it.

Putting it together:

chars = string.ascii_letters + string.digits
def make_string():
    return ''.join(random.choices(chars, k=random.randrange(1, 13)))
def make_n_strings(n):
    return sorted(make_string() for _ in range(n))

This should be simple enough that you can customize it however you want. Want case-insensitive sorting? Just add key=str.upper to the sorted. Want some other distribution of lengths? Just replace the randrange. And so on.

score 1 · Answer 2 · answered Jul 27 '18 at 09:36

You can use the chr() Python 3 function in a loop while generating random number in the ASCII category range you want.

You can find all the ASCII categories here or on Wikipedia.

For exemple :

chr(99)
-> equals c

More information about the chr() function on Python 3 official documentation.

score 0 · Answer 3 · answered Jul 26 '18 at 22:21

0

The simplest way I can think of is

from random import randint
a = ''.join(sorted([chr(randint(33,127)) for i in range(randint(1,20))], reverse = False))
print(a)

reverse = True makes it descending

answered Jul 26 '18 at 22:21

1

or you can use `random.choices(string.ascii_letters + string.digits, k=N)` for a random length N string, from https://stackoverflow.com/a/2257449/5986907 – joel Jul 26 '18 at 22:30

score 0 · Answer 4 · answered Jul 26 '18 at 22:43

There's a lot of ways to do that, and this an easy and simple example to do that in Python 3 using Ascii char codes:-

from random import randint

def generateString(minLength, maxLength):
    result = "";
    resultLength = randint(minLength, maxLength)
    for i in range(resultLength):
        charType = randint(1,3)

        if(charType == 1):
            #number
            result += chr(randint(48, 57))
        elif(charType == 2):
            #upper letter
            result += chr(randint(65, 90))
        elif(charType == 3):
            #lower letter
            result += chr(randint(97, 122))

    return result;

#Example
print(generateString(1,20))

How to generate random increasing or decreasing strings in python?

4 Answers4