Why does the Code only show 'array'

Question

Hello Guys I try to short the content of a post in a preview page. I have tried out the code and it doesn't work. It shows only an 'array' as text. Is this echo wrong or any other failures?

$word=Hello World;


$words = str_word_count($word, 1,'ŠŒŽšœžŸ¥µÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝßàáâãäåæçèéêëìíîïðñòóôõöøùúûüýÿ');
$len = min(50, count($words));
$first_fifty = array_slice($words, 0, $len);
echo $first_fifty;

Thanks for Help...

`Hello World` that and if it's your real code and being unquoted, is a constant; did you define it first? — Funk Forty Niner, Jul 27 '18 at 17:31
`array_slice` returns an array, you can't echo an array directly. Loop it or `implode` it and echo. — AbraCadaver, Jul 27 '18 at 17:34

Razvan Zamfir · Accepted Answer · 2018-07-27T17:59:49.877

0

There are 2 mistakes:

$word=Hello World; should be $word='Hello World';
You are echoing an array; do print_r ($first_fifty); instead;

All the code:

<?php $word='Hello World'; $words = str_word_count($word, 1,'ŠŒŽšœžŸ¥µÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝßàáâãäåæçèéêëìíîïðñòóôõöøùúûüýÿ'); $len = min(50, count($words)); $first_fifty = array_slice($words, 0, $len); print_r ($first_fifty); ?>

You can echo:

<?php
  echo $first_fifty[0] . ' ' . $first_fifty[1];
?>

edited Jul 27 '18 at 17:59

answered Jul 27 '18 at 17:42

Razvan Zamfir

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@RicoRichterYou are welcome any time. – Razvan Zamfir Jul 27 '18 at 18:46

Why does the Code only show 'array'

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