How to get string outside for loop PHP

Question

How I can get $lorem_text as a new string $lorem_outside_text without changing $lorem_text?

for ($i = 0; $i <= 5; $i++) {
  $lorem_text = "lorem\n";
}

$lorem_outside_text = $lorem_text;

echo $lorem_outside_text;

Now result is: lorem

Result should be: lorem lorem lorem lorem lorem

Answer 1

You may use concatenating assignment operator, Please try the following code:

$lorem_text .= "lorem\n";
$lorem_outside_text = '';

for ($i = 0; $i <= 5; $i++) {
  $lorem_outside_text .= $lorem_text;
}

echo $lorem_outside_text;

Answer 2

With this piece of code you are overwriting your existing value every time.

for ($i = 0; $i <= 5; $i++) {
  $lorem_text = "lorem\n"; // this just overwrites $lorem_text value 6 times with same value
}

Instead try to concatenate it using . and also remove extra using of variables here $lorem_outside_text

$lorem_outside_text = ''; //intialize it as empty string
for ($i = 0; $i <= 5; $i++) {
  $lorem_outside_text .= "lorem\n";
}
echo $lorem_outside_text;

Pretty Neat:

<?php
echo str_repeat("lorem\n", 6);
?>

DEMO: https://3v4l.org/CIsCB

Answer 3

You must append the text to the $lorem_text, not overwrite it. Type .= instead of =.

Personally, I'm usually adding text fragments to an array inside a loop, and then concatenate them using implode("\n", $lorem_parts).

Answer 4

Just use str_repeat, that will repeat the string however many times you want.

str_repeat($lorem_text, 5);

Answer 5

Another option is to create an array in the loop that you later implode.

for ($i = 0; $i <= 5; $i++) {
  $lorem_text[] = "lorem";
}



echo implode("\n", $lorem_text);

Implode takes an array and uses the glue to make it string.