So yes it was difficult but i did it without any API
private static List<Class<?>> findClasses(File directory, String packageName) {
List<Class<?>> classes = new ArrayList<Class<?>>();
if (!directory.exists())
return classes;
File[] files = directory.listFiles();
for (File file : files) {
if (file.isDirectory()) {
assert !file.getName().contains(".");
classes.addAll(findClasses(file,
(!packageName.equals("") ? packageName + "." : packageName) + file.getName()));
} else if (file.getName().endsWith(".class"))
try {
classes.add(Class
.forName(packageName + '.' + file.getName().substring(0, file.getName().length() - 6)));
} catch (ClassNotFoundException e) {
System.err.println(e.getMessage());
}
}
return classes;
}
this returns all classes inside a package like TREE command in CMD (if you insert "" as packagne name this will return all classes inside the project).
public static Class<?>[] getClasses(String packageName) {
ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
assert classLoader != null;
String path = packageName.replace('.', '/');
Enumeration<URL> resources = null;
try {
resources = classLoader.getResources(path);
} catch (IOException e) {
System.err.println(e.getMessage());
}
List<File> dirs = new ArrayList<File>();
while (resources.hasMoreElements()) {
URL resource = resources.nextElement();
dirs.add(new File(resource.getFile()));
}
List<Class<?>> classes = new ArrayList<Class<?>>();
for (File directory : dirs)
classes.addAll(findClasses(directory, packageName));
return classes.toArray(new Class[classes.size()]);
}
then this method extract all classes from a package using findClasses() method.