Python requests lib doesn't work with LinkedIn

Question

Sample code:

import requests
print requests.get("https://www.linkedin.com/")

I get: <Response [200]>

Simple curl request does work:

curl "https://www.linkedin.com/"

200 means you made a valid request and got a good response.... — SuperStew, Jul 31 '18 at 15:19
What exactly is the problem? Response 200 means good connection. — Joel, Jul 31 '18 at 15:25
I think OP was expecting `requests` to give back the `HTML` like `curl` does. — K. Dackow, Jul 31 '18 at 15:26
The Response object you're seeing (i.e. ``) contains that data. See [here](https://stackoverflow.com/questions/27803503/get-html-using-python-requests) for accessing it. — K. Dackow, Jul 31 '18 at 15:27
one look at the [documenation](http://docs.python-requests.org/en/master/) would tell you how to fix it. RTM — Paweł Łukasik, Aug 01 '18 at 04:32

score 2 · Answer 1 · answered Jul 31 '18 at 15:21

If you get <Response [200]> that means that it worked properly. You should refer to the documentation for unpacking this Response object to get the data inside of it.

E.g.:

>>> r = requests.get('https://linkedin.com/')
>>> r.text
'<!DOCTYPE html> ...'

score 2 · Answer 2 · answered Jul 31 '18 at 15:32

The requests.get() function returns a Response object that contains attributes about the status_code, headers, and content:

[In]: type(requests.get("https://www.linkedin.com/")

[Out]: <class 'requests.models.Response'>.

I would recommend saving the returned Response into a variable:

response = requests.get("https://www.linkedin.com/")

Then you can access the contents of the Response using response.json() if it is a JSON file or response.text if it is an html page.

In your use case, response.text should return the same thing as curl "https://www.linkedin.com/".

Python requests lib doesn't work with LinkedIn

2 Answers2