ParseFloat String Java

Question

I have this String -> "100,24" and I want join in the var Java type float

But when I have the parse, I get error.

article.cost((Float.parseFloat(array.get(y))));

I need help, ty.

Please rephrase the question so it makes sense, and include any error messages. — Kayaman, Aug 01 '18 at 06:50
Error is For input string: . In my country "Decimal" is with "," — EduBw, Aug 01 '18 at 06:56

score 4 · Accepted Answer · answered Aug 01 '18 at 06:52

4

The number format must contain dot(.) instead of comma(,). That's why you get the exception. However, you can also use parseFloat with String's replace method to convert float by using comma.

class NumberTest {
    public static void main(String[] args) {
        String y = "100,24";
        float num = Float.parseFloat(y.replace(',','.'));
        System.out.println(num);
    }
}

answered Aug 01 '18 at 06:52

Soner from The Ottoman Empire

18,731
3
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It's correct, very thanks – EduBw Aug 01 '18 at 07:01

score 2 · Answer 2 · answered Aug 01 '18 at 07:00

Your issue is the comma, "100,24", that string is not a valid float. So an error will be thrown if you try converting it to one. However if this is what you intended "100.24" that should fix your problem, because that is a valid float type.

So what you do is replace the ',' with a '.' and then try converting. i.e.

String floatStr = "100,24".replace(",", "."); // Change to a correct float value
float newFloat = Float.parse(floatStr); // parse and get your new float

ParseFloat String Java

2 Answers2