json parsing errors "NullPointerException"

Asked Aug 02 '18 at 08:02

Active Aug 02 '18 at 08:22

Viewed 30 times

I got error NullPointerException in Java.

I am just using JSONParser

String test is

{
    "processGroupRevision": {
        "clientId":"f98f0e63-0164-1000-6c10-442b4b1fbe8f",
        "version":1
        },
        "variableRegistry":{
            "variables": [{
                "variable": {
                    "name":"123123123",
                    "value":"12322",
                    "pr": "..." 
                }
            }]
        }
}

And here is the main Code

String test = sb.toString();
System.out.println(test);

JSONParser jsonParser = new JSONParser();
JSONObject jsonObj = (JSONObject) jsonParser.parse(test);
JSONArray jsonArray = (JSONArray) jsonObj.get("variable");

System.out.println("==================");

for (int i=0; i<jsonArray.size(); i++) {
    JSONObject tempObj = (JSONObject) jsonArray.get(i);
    System.out.println(""+(i+1)+" key : " + tempObj.get("name"));
    System.out.println(""+(i+1)+" value : " + tempObj.get("value"));
}

How can I fix this problem? Is it in the For loop ?

edited Aug 02 '18 at 08:22

François Maturel

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asked Aug 02 '18 at 08:02

ko_ma

The `...` doesn't look like valid JSON anyway...? – user202729 Aug 02 '18 at 08:02
1

typo *variables* vs *variable* – Jens Aug 02 '18 at 08:04
1

`variable` and `variables` are too deep within the hierarchy. You need to start from `variableRegistry`. Also as @Jens said you're looking for `variables` since you're attempting to retrieve the array. – Jurgen Camilleri Aug 02 '18 at 08:05
jsonObj.get("variable") -- Does your jsonObj have the property "variable" ? – Quang Dat Pham Aug 02 '18 at 08:06
@ko_ma - about the duplicate closure: Read it, apply to the program, then ask a more specific question such as "why `jsonObj.get("variable")` returns `null`". – user202729 Aug 02 '18 at 08:06

json parsing errors "NullPointerException"

0 Answers0