Swift JSONEncoder().encode for child object

Question

I have a parent class with several methods and attributes:

class Animal {
   var var1: ...
   var var2: ...

   func func1() {}
   func func2() {}
}

And Child class:

class Dog: Animal, Codable {
   var name = ""
}

I need to add to parent class a method, that will return result of JSONEncoder().encode for child class. Something like:

let dog = Dog()
dog.name = "Bob"
let jsonString = dog.jsonString() // {"name":"Bob"}

Can I do this?

Do you want to add this to parent class or do you want to have all animals have `jsonString` method? — Maxim Kosov, Aug 02 '18 at 09:04
@MaximKosov I need that all animals have `jsonString` method or variable — Serhii Didanov, Aug 02 '18 at 09:06

Ashley Mills · Accepted Answer · 2018-08-02T09:07:34.737

1

Just create a String with the result of encode…

extension Encodable {
    func jsonString() -> String {
        let data = try! JSONEncoder().encode(self)
        return String(data: data, encoding: .utf8)!
    }
}

let dog = Dog()
dog.name = "Bob"
dog.jsonString()

// {"name":"Bob"}

edited Aug 02 '18 at 09:07

answered Aug 02 '18 at 09:01

Ashley Mills

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How to get this from something like: `dog.jsonString()`? – Serhii Didanov Aug 02 '18 at 09:07

Swift JSONEncoder().encode for child object

1 Answers1