Syntax Error in Inline if … else Syntax in Python

Question

What exactly is wrong with the syntax and why in the following piece of code? I've counted the parentheses among other things yet am unable to figure it out.

c = ""
 print("Yes") if c else print("No")

Note: It gives a Syntax error like the one below:

print("Yes") if c else print("No")
                            ^
SyntaxError: invalid syntax

Possible duplicate of [Syntax error in if else statement](https://stackoverflow.com/questions/51342536/syntax-error-in-if-else-statement) — Aran-Fey, Aug 03 '18 at 09:31
`print` is a statement in python 2. You can't use statements in a conditional. — Aran-Fey, Aug 03 '18 at 09:31
Possible duplicate of [How to write inline if statement for print?](https://stackoverflow.com/questions/11880430/how-to-write-inline-if-statement-for-print) — Psytho, Aug 03 '18 at 09:31
@Psytho no in 3.6.5... my bad...didnt get OP was asking for 2.7 — B001ᛦ, Aug 03 '18 at 09:34

score 4 · Answer 1 · answered Aug 03 '18 at 09:40

This happens because the print function behaves differently in python2 and python3:
Meanwhile in python3 your code works perfectly, in python2 it raises an error.
This happens because in python2, print is actually a statement and not a function; here you can find a more in-depth QA on the difference between functions and statements.

By the way, you can solve your problem importing the python3 print function from the future:

from __future__ import print_function

c = ""

print("Yes") if c else print("No")

OUTPUT:

No

Syntax Error in Inline if … else Syntax in Python

1 Answers1