How to turn -1.06267582739e+11 into -106267582739.0 in python?

Question

How to suppress scientific notation from a float value in python. Here I tried the following code but it's not working

r_val[v].append('%.2f' % val.get("closing_balance"))

Thanks in advance

...You do realize that `-1.06` isn't anywhere close to `-1.06e+11`, right? — Aran-Fey, Aug 06 '18 at 12:20
yes sorry for that but my point to remove the 'e' from the notation — Charles Michel, Aug 06 '18 at 12:21
Well, at least you should first get rid of the `e+11` part by multiplying by `e-11` if that's not relevant for you (python doesn't know that!). — toti08, Aug 06 '18 at 12:23
I only just realized... there's nothing wrong with the code you posted? `'%.2f'%-1.06267582739e+11` returns `'-106267582739.00'` as it should. What's the problem with that code? — Aran-Fey, Aug 06 '18 at 15:07

score 1 · Accepted Answer · answered Aug 06 '18 at 12:24

Using format(x, '.#f')

consider this snippet:

x = 0.000000235
print(x)
2.35e-07
print (format(x, '.9f'))
0.000000235

Or, to go closer to your question:

y = -1.06267582739e-11  # note I changed '+' to '-' since '+' is is just represented as a regular float

    print(y)
    -1.06267582739e-11

    print(format(y,'.22f'))
    -0.0000000000106267582739

How to turn -1.06267582739e+11 into -106267582739.0 in python?

1 Answers1