Swift: Order array with same values

Question

I have a 2D array with multiples values.

One field on this array is called group, let's imagine my array have this order:

private var myArray = [
   ArrayModel(
      id: 0,
      name: "Test",
      color: 0,
      img: "img.png",
      group = "myGroup"),
   ArrayModel(
      id: 1,
      name: "Test1",
      color: 0,
      img: "img.png",
      group: "myGroup"),
   ArrayModel(
      id: 2,
      name: "Test2",
      color = 0,
      img = "img.png",
      group = "myGroup3")
   ArrayModel(
      id: 3,
      name: "Test3",
      color: 0,
      img: "img.png",
      group: "myGroup2"),
   ArrayModel(
      id: 4
      name: "Test4"
      color: 0
      img: "img.png"
      group: "myGroup3")
]

Array Model

class ArrayModel: Decodable {

var id: Int
var name: String
var color: Int
var img: String
var group: String

convenience init() {
    self.init()
    id = 0
    name = ""
    color = 0
    img = ""
    group = ""
}

init(id: Int, name: String, color: Int, img: String, group: String) {
    self.id = id
    self.name = name
    self.color = color
    self.img = img
    self.group = group
}

}

How can I move my myArray[2] to be in myArray[1] ?

My desired output is :

let myArray = [
   ArrayModel(
      id: 0,
      name: "Test",
      color: 0,
      img: "img.png",
      group: "myGroup")
   ]
   [1] => same shema, but group => "myGroup"
   [2] => same shema, but group => "myGroup2"
   [3] => same shema, but group => "myGroup2"
   [4] => same shema, but group => "myGroup3"
]

I tried this :

myArray.sorted(by: { $0.group < $1.group })

Thanks for your help!

Please can you show your exact input and desired output? (as well as any code you've tried?) — Adi219, Aug 08 '18 at 08:49
It's not clear what you're asking - a (deleted) answer correctly showed how to move `myArray[2]` to `myArray[1]` — Ashley Mills, Aug 08 '18 at 08:51
It is edited now. Sorry for the wrong formulation, it's a bit hard to explain myself on problems like this :-) — Romain Sickenberg, Aug 08 '18 at 08:53
@Adi219 Same array with keys, values changes, in this case, only group change — Romain Sickenberg, Aug 08 '18 at 08:56
You say it's a 2D array but it looks more like an array of dictionaries or structs. Could you show us some real code instead of this pseudo code? — Joakim Danielson, Aug 08 '18 at 08:58
I've edited your question to show my understanding of what `myArray` initially looks like. Am I correct? (If not, feel free to roll back the edit) — Adi219, Aug 08 '18 at 08:59
@Adi219 Thanks, it's almost correct, but I edited it, I will post some code — Romain Sickenberg, Aug 08 '18 at 09:01
The code with which you initialise your array is wrong. You should be initialising the structs, not an array with a semi-JSON dictionary containing the arguments of the struct. — regina_fallangi, Aug 08 '18 at 09:05
@NiravD Actually, they don't need the `by: ... ` bit. See https://stackoverflow.com/a/24130058/7908770 — Adi219, Aug 08 '18 at 09:12
@Adi219 if you write closure in `()` then you need to use first parameter argument `by` — Nirav D, Aug 08 '18 at 09:15
@Adi219 It doesn't related to add by or not its related with `sort` and `sorted` method — Nirav D, Aug 08 '18 at 09:20
@NiravD I'm not quite sure about what you mean, but it's definitely relevant here as the OP isn't using `sorted` appropriately here. — Adi219, Aug 08 '18 at 09:21
@regina_fallangi I'm 100% sure this is wrong, I append my array like a normal array, with this : `JSONDecoder().decode(jsonStruct.self, from: json)` — Romain Sickenberg, Aug 08 '18 at 09:28
@RomainSickenberg without the piece of code you just posted, that would be wrong. Make sure to always post all of your code. — regina_fallangi, Aug 08 '18 at 09:35

Pranavan SP · Answer 1 · 2018-08-08T09:25:03.423

1

This may help you to sorted by Case Sensitive but your myArray should be mutable. ex : var myArray

myArray = myArray.sorted(by: { $0.group.localizedCompare($1.group) == .orderedAscending})

edited Aug 08 '18 at 09:25

answered Aug 08 '18 at 09:07

Pranavan SP

1,785
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Adi219 · Accepted Answer · 2018-08-08T09:22:28.927

1

Try this:

myArray.sort { $0.group < $1.group }

The .sort(by: ...) isn't what you need here, as you want to modify myArray (by sorting it). To do that, you have to omit the by:....

For more information, see this answer :)

edited Aug 08 '18 at 09:22

answered Aug 08 '18 at 09:08

Adi219

4,712
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This doesn't make sense `sorted` return sorted array its not mutable method – Nirav D Aug 08 '18 at 09:17
Check the apple doc https://developer.apple.com/documentation/swift/array/2296815-sorted it will return sorted array you need to store the result, sort is the mutating method https://developer.apple.com/documentation/swift/array/2296801-sort – Nirav D Aug 08 '18 at 09:18
@NiravD Please see https://stackoverflow.com/questions/24130026/swift-how-to-sort-array-of-custom-objects-by-property-value/24130058#24130058 – Adi219 Aug 08 '18 at 09:19
2

If you check the answer it is using `sort` method not the `sorted` check apple doc – Nirav D Aug 08 '18 at 09:21
@NiravD Yep, you're right! What you've been saying makes sense. Edited my answer :) – Adi219 Aug 08 '18 at 09:22
No, sorted was right, with `sort` I have an error `Value of tuple type '()' has no member 'subscript'` – Romain Sickenberg Aug 08 '18 at 09:31

Swift: Order array with same values

Array Model

My desired output is :

2 Answers2