when i build shell script am getting the below error, since am new to CentOS am not able to find out the cause can anyone help me regarding this ??
I guess we need to pass command line parameter while executing am not sure what has to be passed as parameter here.
Shell-script :
#!/bin/sh
# Default place to look for apr source. Can be overridden with
# --with-apr=[directory]
apr_src_dir=../apr
while test $# -gt 0
do
# Normalize
case "$1" in
-*=*) optarg=`echo "$1" | sed 's/[-_a-zA-Z0-9]*=//'` ;;
*) optarg= ;;
esac
case "$1" in
--with-apr=*)
apr_src_dir=$optarg
;;
esac
shift
done
if test -d "$apr_src_dir"
then
echo ""
echo "Looking for apr source in $apr_src_dir"
else
echo ""
echo "Problem finding apr source in $apr_src_dir."
echo "Use:"
echo " --with-apr=[directory]"
exit 1
fi
# Remove some files, then copy them from apr source tree
rm -f build/apr_common.m4 build/find_apr.m4 build/install.sh \
build/config.guess build/config.sub build/mkdir.sh \
build/make_exports.awk build/make_var_export.awk \
build/get-version.sh
cp $apr_src_dir/build/apr_common.m4 $apr_src_dir/build/find_apr.m4 \
$apr_src_dir/build/install.sh $apr_src_dir/build/config.guess \
$apr_src_dir/build/config.sub $apr_src_dir/build/mkdir.sh \
$apr_src_dir/build/make_exports.awk $apr_src_dir/build/make_var_export.awk \
$apr_src_dir/build/get-version.sh \
build
Error obtained :
[root@localhost apr-iconv]# sh buildconf
buildconf: line 2: $'\r': command not found
buildconf: line 6: $'\r': command not found
buildconf: line 10: syntax error near unexpected token `$'in\r''
'uildconf: line 10: ` case "$1" in
Thank you :)