Pass arguments to Print

Asked Aug 10 '18 at 18:16

Active Aug 10 '18 at 18:16

Viewed 28 times

I want a class to use a modified 'print' function which only outputs when an internal flag is set:

def __quietprint(self, *args):
    if not self.silent:
        print(args)

The desired output, when self.silent is False, would be e.g.

self.__quietprint("E:", "-1.24")
% E: -1.24  #desired behaviour

However, the code as written, unsurprisingly in hindsight, instead outputs the tuple of *args:

self.__quietprint("E:", "-1.24")
% ("E:", -1.24)  #actual behaviour

How can I achieve the desired effect?

asked Aug 10 '18 at 18:16

AGML

3

You need to unpack the args into the call to `print`: `print(*args)` – Patrick Haugh Aug 10 '18 at 18:20
That indeed works. I hadn't done it because my syntax checker incorrectly flags it as erroneous. Thanks! – AGML Aug 10 '18 at 18:21
2

Make sure your syntax checker is set to Python 3 and not Python 2. – Patrick Haugh Aug 10 '18 at 18:22

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