java.lang.ArrayIndexOutOfBoundsException When I try to add a variable to an Array

Question

I'm trying to save numbers to an array through Scanner Input but
"java.lang.ArrayIndexOutOfBoundsException" keeps popping up.

Here is my code:

for (int counter = 1;1==1;counter++) {
            int bucky[] = new int[counter];
            int scan = oof.nextInt();
            bucky[counter] = scan;
            if (counter == 5) {
                System.out.println(bucky);
            }

Can someone explain what I'm doing wrong or where I'm going wrong in my thought process?

What is the first index of an array? Assuming its length is 1, what is its last index? https://docs.oracle.com/javase/tutorial/java/nutsandbolts/arrays.html — JB Nizet, Aug 12 '18 at 07:47
in additiion to previous comment: 1) move array creation out of the for-loop. 2) Why not use `ArrayList` instead of array? — Max Farsikov, Aug 12 '18 at 08:13

score 0 · Answer 1 · answered Aug 12 '18 at 07:45

0

Try

for (int counter = 1;1==1;counter++) {
            int bucky[] = new int[counter];
            int scan = oof.nextInt();
            bucky[counter-1] = scan;
            if (counter == 5) {
                System.out.println(bucky);
            }

One array of 5 positions {0,1,2,3,4}

Your Array have 1 position {0}

bucky[counter-1] = scan;

answered Aug 12 '18 at 07:45

Renan César

1

im getting werid outputs like [I@16d3586 – DudeManGuy Aug 12 '18 at 07:48
is this a glitch in the compiler or something – DudeManGuy Aug 12 '18 at 07:50
@DudeManGuy https://stackoverflow.com/questions/409784/whats-the-simplest-way-to-print-a-java-array – JB Nizet Aug 12 '18 at 07:50
@DudeManGuy handy rule of thumb: it's **never** a glitch the compiler (;->) – Kevin Anderson Aug 12 '18 at 08:15

java.lang.ArrayIndexOutOfBoundsException When I try to add a variable to an Array

1 Answers1