Object inside a object convert to single object

Question

Is it possible to flatten nested array object to single object.In my query i want to remove the source object and make the resultant object as one object (I have mentioned my output also).

    var result = [
    {"_id":"12345",
    "_type":"feeds",
    "_source":{
              "title": "hi all solve it",
              "link": "www.face.com",
              "content": "Hi thewwewewedwe asdasdasdasd",
              "createdAt": "2018-08-08T11:42:40.073Z",
              "updatedAt": "2018-08-08T11:42:40.073Z",
              "reply": []
                }
    }]

 //resultant array

     var newResult = [
        {
            "_id":"12345",
            "_type":"feeds",
            "title": "hi all solve it",
            "link": "www.face.com",
            "content": "Hi thewwewewedwe asdasdasdasd",
            "createdAt": "2018-08-08T11:42:40.073Z",
            "updatedAt": "2018-08-08T11:42:40.073Z",
            "reply": []
        }];

Yes, it is very possible. What have you researched so far? – mplungjan Aug 20 '18 at 13:21 — mplungjan, Aug 20 '18 at 13:21
I tried using reduce but didn't work for me – deepak masakale Aug 20 '18 at 13:30 — deepak masakale, Aug 20 '18 at 13:30
No need for a reduce. See my answer using a plain map – mplungjan Aug 20 '18 at 13:35 — mplungjan, Aug 20 '18 at 13:35

Lyubomir · Answer 1 · 2018-08-20T13:31:50.043

1

You could use ...spread for that

var result = [{
  "_id":"12345",
  "_type":"feeds",
  "_source": {
    "title": "hi all solve it",
    "link": "www.face.com",
    "content": "Hi thewwewewedwe asdasdasdasd",
    "createdAt": "2018-08-08T11:42:40.073Z",
    "updatedAt": "2018-08-08T11:42:40.073Z",
    "reply": []
  }
}];
    

const { _source, ...rest } = result[0];

const flattenResult = [{
  ...rest,
  ..._source,
}];

console.log(flattenResult);

Leaving the solution for result.length > 1 to you as an exercise.

edited Aug 20 '18 at 13:31

answered Aug 20 '18 at 13:23

Lyubomir

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And for more than one object in the loop? – mplungjan Aug 20 '18 at 13:28
What if i had list of nested object with same structure will this work – deepak masakale Aug 20 '18 at 13:29
I will leave this as an exercise for you :) hint: use map or forEach or a regular loop – Lyubomir Aug 20 '18 at 13:30
@deepakmasakale I have that in my answer – Ankit Agarwal Aug 20 '18 at 13:31
Thanks for the answer @lustoykov – deepak masakale Aug 20 '18 at 13:31
1

try to research it yourself, this is not that complicated, you should learn to research yourself if you want to become a good developer. best of luck! – Lyubomir Aug 20 '18 at 13:32
I will @lustoykov – deepak masakale Aug 20 '18 at 15:47

score 0 · Answer 2 · answered Aug 20 '18 at 13:26

You can first loop through the array to get each of the object in the array and then loop through the object keys to get the key names. Then if you encounter the key with name _source then assign those object content into the flatten object using Object.assign(). This will work for result array with one or more than one object.

var result = [{
  "_id": "12345",
  "_type": "feeds",
  "_source": {
    "title": "hi all solve it",
    "link": "www.face.com",
    "content": "Hi thewwewewedwe asdasdasdasd",
    "createdAt": "2018-08-08T11:42:40.073Z",
    "updatedAt": "2018-08-08T11:42:40.073Z",
    "reply": []
   }
},
{
  "_id": "1234567",
  "_type": "feeds123",
  "_source": {
    "title": "hi all solve it 123",
    "link": "www.face.com",
    "content": "Hi thewwewewedwe asdasdasdasd",
    "createdAt": "2018-08-08T11:42:40.073Z",
    "updatedAt": "2018-08-08T11:42:40.073Z",
    "reply": []
  }
}];
var newArray = [];
result.forEach(function(obj){
  var tempObj = {};
  Object.keys(obj).forEach(function(key){
    if(key !== '_source'){
      tempObj[key] = obj[key];
    } else {
      tempObj = Object.assign(tempObj,  obj[key]);
    }
  });
  newArray.push(tempObj);
});
console.log(newArray);

All that code. And again you are answering a non-researched question. This is much shorter: `result = result.map(function(item) { var obj = item._source; for (var o in item) { if (o != "_source") obj[o] = item[o]; } return obj; })` — mplungjan, Aug 20 '18 at 13:28
Read my comment to the question. We should not encourage asking "gimme teh codez" type questions. But if you insist. — mplungjan, Aug 20 '18 at 13:29

score 0 · Accepted Answer · answered Aug 20 '18 at 13:30

0

Simplest version using plain JS

Handles more than one entry

var result = [{ "_id": "12345", "_type": "feeds", "_source": { "title": "hi all solve it", "link": "www.face.com", "content": "Hi thewwewewedwe asdasdasdasd", "createdAt": "2018-08-08T11:42:40.073Z", "updatedAt": "2018-08-08T11:42:40.073Z", "reply": [] } },{ "_id": "12346", "_type": "feeds", "_source": { "title": "hi all solve it", "link": "www.face.com", "content": "Hi thewwewewedwe asdasdasdasd", "createdAt": "2018-08-08T11:42:40.073Z", "updatedAt": "2018-08-08T11:42:40.073Z", "reply": [] } }]

result = result.map(function(item) {
  var obj = item._source;
  for (var o in item) {
    if (o != "_source") obj[o] = item[o];
  }
  return obj;
})
console.log(result)

answered Aug 20 '18 at 13:30

mplungjan

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All that code ... ;) – Jonas Wilms Aug 20 '18 at 14:02
@JonasWilms where is yours? I did not use ES6 because it’s hard to read for noobs and not running in IE without Babel – mplungjan Aug 20 '18 at 14:35
Thanks for the answer mr @mplungjan . NAMASTE :) – deepak masakale Aug 20 '18 at 15:51
noted @mplungjan – deepak masakale Aug 20 '18 at 16:08

Object inside a object convert to single object

3 Answers3