python store array slices a[n:m] b[n:m]

Question

How can I store where I will slice if I have multiple arrays?
Instead of having this:

a1[5:8]
a2[5:8]
b1[5:8]

I have:

slicePart = [5:8]

a1[slicePart]
a2[slicePart]
b1[slicePart]

I don't know if I fully understand your question but you could use variable: `start = 5 end = 8 a1[start:end]` — Exho, Aug 20 '18 at 14:48
you can store 5 and 8 independently, like `start=5, end=8, a1[start:end]` — smagnan, Aug 20 '18 at 14:49

score 2 · Accepted Answer · answered Aug 20 '18 at 14:49

The slicing syntax is simply syntactic sugar for passing a slice object. So you can use:

slicepart = slice(5, 8)

So, you can play around with:

In [21]: class MyObj:
    ...:     def __getitem__(self, item):
    ...:         print(item)
    ...:

In [22]: obj = MyObj()

In [23]: obj[5]
5

In [24]: obj[5:8]
slice(5, 8, None)

In [25]: obj[5, 8]
(5, 8)

python store array slices a[n:m] b[n:m]

1 Answers1