the first half of the code works fine, but the second half it is giving me that warning on the title, I just cant find why
//first half
$sql = "SELECT id, password FROM users WHERE username=?;";
$stmt = mysqli_stmt_init($conn);
mysqli_stmt_prepare($stmt,$sql);
mysqli_stmt_bind_param($stmt, 's', $username);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
$row = mysqli_fetch_assoc($result);
$id = $row["id"];
mysqli_free_result($result);
mysqli_stmt_close($stmt);
//second half
$sql = "CREATE TABLE ? (id int(11) NOT NULL AUTO_INCREMENT, noteId int(11), noteName varchar(255));";
$stmt = mysqli_stmt_init($conn);
echo(gettype($id));
mysqli_stmt_prepare($stmt,$sql);
//the next bind, execute and close are giving me the warning
mysqli_stmt_bind_param($stmt,'i',$id);
mysqli_stmt_execute($stmt);
mysqli_stmt_close($stmt);