Sort by coordinates inside of a list, inside of a list

Question

I have a program where I want to sort by an x coordinate.

My list looks like this:

[('Name1', (449, 923, 634, 737)), ('Name2', (390, 1356, 613, 1133)), ('Name3', (1062, 1749, 1216, 1594))]

Each element of the original list has a name, and then a set of x1, y1, x2, y2 coordinates. If I want to sort my list by the x2 coordinate, how would I do that?

I've searched around and found that you can use "itemgetter" to do something like this:

preds = sorted(preds, key=itemgetter(1))

But that is getting the whole set of coordinates. How would I sort by say, the third coordinate, specifically?

Another dup: [Sort a nested list in python by inner list number](https://stackoverflow.com/q/41736425/2823755) — wwii, Aug 27 '18 at 15:07
Thank you very much! I knew it was so simple, but for some reason I was stuck. — Xrae, Aug 27 '18 at 15:11

score -1 · Accepted Answer · answered Aug 27 '18 at 14:59

You can sort it with key=lambda t:t[1][2]

>>> preds = [('Name1', (449, 923, 634, 737)), ('Name2', (390, 1356, 613, 1133)), ('Name3', (1062, 1749, 1216, 1594))] 
>>> preds.sort(key=lambda t: t[1][2])
>>> preds
[('Name2', (390, 1356, 613, 1133)), ('Name1', (449, 923, 634, 737)), ('Name3', (1062, 1749, 1216, 1594))]
>>>

Sort by coordinates inside of a list, inside of a list

1 Answers1