Printing elements of a set in python

Question

I want to print the elements of the set consecutively, so I wrote the following code:

s='dmfgd'
print(set(s))

However, this code shows the output as:

set(['m', 'd', 'g', 'f'])

but, I want output like:

set(['d','m','f','g'])

Any help will be appreciated.

`list(dict(zip(s,s)))` should solve your issue – Onyambu Aug 30 '18 at 06:30 — Onyambu, Aug 30 '18 at 06:30
Or: `print(sorted(set(s),key=s.index))` – U13-Forward Aug 30 '18 at 06:47 — U13-Forward, Aug 30 '18 at 06:47

blhsing · Accepted Answer · 2021-03-08T02:07:01.653

4

Set is unordered. You can instead use a list of dict keys to emulate an ordered set if you're using Python 3.6+:

print(list(dict.fromkeys(s)))

This outputs:

['d', 'm', 'f', 'g']

edited Mar 08 '21 at 02:07

answered Aug 30 '18 at 06:25

blhsing

score 1 · Answer 2 · answered Aug 30 '18 at 06:20

1

Python set is unordered collections of unique elements

Try:

s='dmfgd'

def removeDups(s):
    res = []
    for i in s:
        if i not in res:
            res.append(i)
    return res

print(removeDups(s))

Output:

['d', 'm', 'f', 'g']

answered Aug 30 '18 at 06:20

Rakesh

2 Answers2