insert different value to object as json

Question

i want my json like this

{"struct":{"member":[{"name":"Testname","value":{"string":"TestString"}},{"name":"Testname2","value":{"string":"TestString2"}}]}}

but when i run the code the result is like this

{"struct":{"member":[{"name":"Testname","value":{"string":"TestString2"}},{"name":"Testname2","value":{"string":"TestString2"}}]}}

this is my code

Stringcont.setstring("TestString");
Stringcont.setstring("TestString2");
Membercont.add(new Membercont("Testname",Stringcont));
Membercont.add(new Membercont("Testname2",Stringcont));

Structcont.setmember(Membercont);
Objectcont.setstruct(Structcont);
Gson gson = new Gson();
System.out.println(gson.toJson(Objectcont));

this is because you add the same object with different keys, try instantiating another object rather. — Incepter, Aug 31 '18 at 10:24

muzychuk · Answer 1 · 2018-08-31T10:22:22.970

2

You are setting the same Stringcont object twice. First time to "TestString", then to "TestString2". Try using the add method before setting it to "TestString2" or use different objects.

Stringcont.setstring("TestString");
Membercont.add(new Membercont("Testname",Stringcont));
Stringcont.setstring("TestString2");
Membercont.add(new Membercont("Testname2",Stringcont));

edited Aug 31 '18 at 10:22

answered Aug 31 '18 at 10:19

muzychuk

288
1
2
13

1

are you using any pojo class if yes please share i will tell how you can do that – harkesh kumar Aug 31 '18 at 10:21
thank you, but i want to insert different value in same object. – Andika Ristian Nugraha Aug 31 '18 at 10:21
what does pojo class means? sorry i'm newbie in java @harkeshkumar – Andika Ristian Nugraha Aug 31 '18 at 10:23
1

can you clarify what you mean by "different value in same object"? – Alvaro Lemos Aug 31 '18 at 10:24
1

class that have getter and setter – harkesh kumar Aug 31 '18 at 10:25
@AndikaRistianNugraha Refer, https://stackoverflow.com/questions/12517905/what-is-java-pojo-class-java-bean-normal-class – Pallav Kabra Aug 31 '18 at 10:36
@AlvaroLemos, if you look at the code the value of object "Stringcont" is changing to "TestingString2" before adding "TestingString" to "Membercont" object. So, if you look at the solution provided, we are first adding "TestingString" then adding "TestingString2". – Pallav Kabra Aug 31 '18 at 10:45
@PallavKabra I see now, makes sense – Alvaro Lemos Aug 31 '18 at 10:54

insert different value to object as json

1 Answers1