is it possible to use the multiple cases in "if condition" to access the same function

Question

I need to access the same function for all the cases so I implemented the multiple cases in the if condition. as IDE Throws an error for this, it is obvious that this is the wrong implementation. But is there something which can be an alternative to such logic.

java

 void movie() {
                int m;
                System.out.println("Choose the movie :");
                System.out.println("1.BAHUBALI\n2.SHIVAAY\n3.DANGAL\n4.AIRLIFT");
                m =sc.nextInt();
          switch(m){
                if(case 1: || case 2: || case 3: || case 4:) {
                     Payment();
                }

                else {
                    System.out.println("Choosen an Invlid option");
                }
            }
        }

Do take a look at rephrased [switch labels](https://stackoverflow.com/a/52238221/1746118)... — Naman, Sep 08 '18 at 18:34

score 7 · Accepted Answer · answered Sep 01 '18 at 03:35

7

Try this:-

switch (key) {
        case 1:
        case 2:
        case 3:
        case 4: 
            Payment();
            break;

        default:
            System.out.println("Choosen an Invlid option");
            break;
        }

answered Sep 01 '18 at 03:35

vinay chhabra

587
3
7

Ashishkumar Singh · Answer 2 · 2018-09-07T03:13:48.330

Since you are doing Integer comparison here, you could use Map to reduce the comparison to only one condition. Something like below

    Map<String, Integer> map = new HashMap<>();
    map.put("1", 1);
    map.put("2", 2);
    map.put("3", 3);
    map.put("4", 4);

    void movie() {
    int m;
    System.out.println("Choose the movie :");
    System.out.println("1.BAHUBALI\n2.SHIVAAY\n3.DANGAL\n4.AIRLIFT");
    m = sc.nextInt();

    if (map.containsKey(m)) {
        Payment();
    }
    else {
        System.out.println("Choosen an Invlid option");
    }
}

Map.containsKey : Returns true if this map contains a mapping for the specified key.

So, initially we are putting the value that we are expecting from the user in Map object and then, checking if the actual user input is present in the object using containsKey. If it is then call, Payment() else, println some message

can you explain shortly? – Aniket Jadhav Sep 06 '18 at 22:29 — Aniket Jadhav, Sep 06 '18 at 22:29
@AniketJadhav Updated my answer. Kindly have a look – Ashishkumar Singh Sep 07 '18 at 03:14 — Ashishkumar Singh, Sep 07 '18 at 03:14

is it possible to use the multiple cases in "if condition" to access the same function

2 Answers2