Regex: decimal positive numbers accepted, but not starting with point

Asked Sep 04 '18 at 08:35

Active Sep 04 '18 at 09:30

Viewed 40 times

I'm quite new with regular expression, i'm using it in angularjs. I need to check an input field, and I need to accept only positive decimal values with no more than 3 digits after the point:

and reject values like

0
0.
.
.6
.635
3.6589

I tried this regexp:

var result = /([1-9]\d*)\.(\d{1,3})/.test(value) || /[1-9]\d*(?=\s|$)/.test(value);

and more or less it works, but still

it accepts values with more than 3 digits after the point, like 45.9876
it accepts .356 values (a number starting with . )

what I'm missing?

edited Sep 04 '18 at 09:30

asked Sep 04 '18 at 08:35

Don Diego

1,309
3
23
46

1

Using ^\d+(?:\.\d{1,2})?$ is a good idea, but my problem is that if you put 0, then you MUST put a decimal value, like 0.65, because 0 is not accepted. Moreover, .36 and 000.00 should not be accepted. – Don Diego Sep 04 '18 at 08:55
try this ^[1-9]+(\.[0-9]{1,3})?$ – Rakesh Kumar Sep 04 '18 at 09:31
thanks @RakeshKumar, I already tried but this way it does not accepts values like 0.35 or 0.658 – Don Diego Sep 04 '18 at 09:41
1

I guess that the correct answer is "^[0-9]+\.[0-9]{1,3}$" – michoprogrammer Sep 04 '18 at 10:03
thanks!! this works =) – Don Diego Sep 04 '18 at 10:04

Regex: decimal positive numbers accepted, but not starting with point

0 Answers0