Repeating function n times printx

Question

Write a function called printx() that just prints the letter "x". Then write a function called multiplex() which takes as argument an integer and prints as many times the letter "x" as the integer indicates by calling the function printx() that many times.

I already came up with this

def printx():
    print ("x")
printx()

But I do not know how to proceed, some help is appreciated;)

Any suggestions?

Possible duplicate of [How do I call a function twice or more times consecutively in python?](https://stackoverflow.com/questions/9047985/how-do-i-call-a-function-twice-or-more-times-consecutively-in-python) — BallpointBen, Sep 04 '18 at 16:10

score 0 · Answer 1 · answered Sep 04 '18 at 16:07

0

@Sjeng here is the code that you are looking for. Hope this helps you.

def printx():
    print('x')

def muliplex(num): # num is the number of times you want x to be printed
    for i in range(num):
        printx()

answered Sep 04 '18 at 16:07

Akhilesh Pandey

868
8
18

def printx(): print('x') printx() def muliplex(8): # num is the number of times you want x to be printed for i in range(8): printx() I did this, but still got an error message. – Sjeng Sep 04 '18 at 16:22
@Sjeng It works for me. Could you please send me the error message and if possible also a screenshot of your code? Would be glad to help you. – Akhilesh Pandey Sep 05 '18 at 03:02

Repeating function n times printx

1 Answers1