How to search for a pattern in a file and store it in a variable using shell script? Please give an example

Question

suppose in a file if I have " Route : 8888" , I want to get the string after the pattern "Route :"

I have used sed command, but it is printing 8888 but I want to store it into a variable and use for further processing

bipll · Accepted Answer · 2018-09-06T14:11:46.210

0

So store sed's output in a variable:

ROUTE_VALUE=$(sed ... <file.txt)

Where '...' is your sed command.

$ cat rt.sh
ROUTE=`sed -n 's/.*Route = \(.*\),.*/\1/p' data.txt`
echo $ROUTE
$ bash rt.sh
8888
$ source rt.sh
8888

edited Sep 06 '18 at 14:11

answered Sep 06 '18 at 12:15

bipll

The following is my sed command sed -n 's/.*Route = $.*$,.*/\1/p' data.txt I did this as u suggested ROUTE=$(sed ... – Rahama Tulla Sep 06 '18 at 12:24
ROUTE=$(sed -n 's/.*Route = $.*$,.*/\1/p' data.txt) echo "$ROUTE" this is giving illegal variable name – Rahama Tulla Sep 06 '18 at 12:34
Okay, rename it to something, I've picked a random name. – bipll Sep 06 '18 at 12:38
Code: ROUTE=`sed -n 's/.*Route = $.*$,.*/\1/p' data.txt` OUTPUT: ROUTE=8888: Command not found – Rahama Tulla Sep 06 '18 at 12:54
Unsure how you do it, I've added an example. – bipll Sep 06 '18 at 13:09
Thank you for the example. I used command source rt.sh rather than bash rt.sh .. What is the difference – Rahama Tulla Sep 06 '18 at 13:28
`source` reads commands and executes them in current shell. `bash rt.sh` runs bash as a separate process that executes the script. – bipll Sep 06 '18 at 14:12

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