Java Loop alternate Values

Question

So saying I had this Loop

for (int i = 0; i < InfomationText.length; i++) {
       System.out.println("Hello World");
}

But every second time it loops 1 value I need the string to "Hello World1"

Eg

Index 0: = Hello World
Index 1: = Hello World1
Index 2: = Hello World
Index 3: = Hello World1

Thanks in advance.

Do you know how to check if `i` is even? Then you can just decide what's printed. — Carcigenicate, Sep 06 '18 at 16:51
I can strongly recommend reading through the [java basics](https://docs.oracle.com/javase/tutorial/java/nutsandbolts/index.html) documentation. It doesn't take super long, and gives you the basics that let you figure out what the language can even do at the fundamental level, such as here. You can easily write something that checks whether "right now" is "every second time", but not if you haven't read through what basics the language supports. — Mike 'Pomax' Kamermans, Sep 06 '18 at 16:54
possible duplicate of https://stackoverflow.com/questions/7342237/check-whether-number-is-even-or-odd although to be fair that's kind of x-y. This problem could be solved by adding i++; and then System.out.println("Hello World1"); — Jeutnarg, Sep 06 '18 at 16:55

Acapulco · Accepted Answer · 2019-06-04T17:27:24.190

1

Like Cargigenicate's comment says, you can check if i is odd or even:

for (int i = 0; i < 10; i++) {
    if(i % 2==0){
        System.out.println("Hello World");
    }
    else{
        System.out.println("Hello World1");
    }
}

edited Jun 04 '19 at 17:27

answered Sep 06 '18 at 16:54

Acapulco

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score 1 · Answer 2 · answered Sep 06 '18 at 16:54

I'd add something like this to the loop body:

if(i%2 == 0) {
    System.out.println("Hello World");
} else {
    System.out.println("Hello World1");
}

Alternately, you could append to your string in the if, and then have one System.out.println():

String greeting = "Hello World";
if(i%2 == 1) {
    greeting = greeting + "1";
}
System.out.println(greeting);

Java Loop alternate Values

2 Answers2