Getting Raw XML From SOAPMessage in Java

Question

I've set up a SOAP WebServiceProvider in JAX-WS, but I'm having trouble figuring out how to get the raw XML from a SOAPMessage (or any Node) object. Here's a sample of the code I've got right now, and where I'm trying to grab the XML:

@WebServiceProvider(wsdlLocation="SoapService.wsdl")
@ServiceMode(value=Service.Mode.MESSAGE)
public class SoapProvider implements Provider<SOAPMessage>
{
    public SOAPMessage invoke(SOAPMessage msg)
    {
        // How do I get the raw XML here?
    }
}

Is there a simple way to get the XML of the original request? If there's a way to get the raw XML by setting up a different type of Provider (such as Source), I'd be willing to do that, too.

score 171 · Answer 1 · edited Jul 19 '13 at 12:53

171

You could try in this way.

SOAPMessage msg = messageContext.getMessage();
ByteArrayOutputStream out = new ByteArrayOutputStream();
msg.writeTo(out);
String strMsg = new String(out.toByteArray());

edited Jul 19 '13 at 12:53

palacsint

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answered Sep 29 '09 at 03:22

Smith Torsahakul

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This doesn't take character encoding into account – artbristol Nov 19 '13 at 17:35
Will it consume much memory with something like constructing DOM objects or the like? Or will it really give the raw string from the HTTP response without internally parsing the xml? – Ruslan Mar 28 '16 at 20:38
@artbristol : you can use String class other constructor i.e. String(out.toByteArray(),StandardCharsets.UTF_8) for handling character encoding – Ashish Kathait Jan 06 '22 at 15:02
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Sigh. 166 upvotes so far. Please *don't* use this answer. You will mangle your 'special characters'. You can't use the String constructor idea suggested by Ashish, because you would need to specify the character encoding in the source code at compile time, but you don't know it until runtime. Please use my answer. – artbristol Mar 07 '23 at 10:38
Just what I needed! Gonna save it for future use. – Alain Cruz Apr 04 '23 at 15:32

artbristol · Answer 2 · 2013-11-20T08:58:47.203

If you have a SOAPMessage or SOAPMessageContext, you can use a Transformer, by converting it to a Source via DOMSource:

            final SOAPMessage message = messageContext.getMessage();
            final StringWriter sw = new StringWriter();

            try {
                TransformerFactory.newInstance().newTransformer().transform(
                    new DOMSource(message.getSOAPPart()),
                    new StreamResult(sw));
            } catch (TransformerException e) {
                throw new RuntimeException(e);
            }

            // Now you have the XML as a String:
            System.out.println(sw.toString());

This will take the encoding into account, so your "special characters" won't get mangled.

Is provided solustion memory-consuming? – lospejos Jul 13 '16 at 15:05 — lospejos, Jul 13 '16 at 15:05

score 13 · Answer 3 · answered Sep 11 '14 at 09:42

13

for just debugging purpose, use one line code -

msg.writeTo(System.out);

answered Sep 11 '14 at 09:42

Shahadat Hossain Khan

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The OP is not necessarily debugging to System.out (which isn't necessarily conveniently accessible for a webserver)--he/she might need to send the original XML over a socket, store it somewhere, or calculate its statistics. – nanofarad Sep 11 '14 at 10:19
You can easily write to a `ByteArrayOutputStream` convert to `String`... seems easy to me – vikingsteve Aug 17 '16 at 12:38

score 13 · Accepted Answer · edited Aug 23 '12 at 14:48

It turns out that one can get the raw XML by using Provider<Source>, in this way:

import java.io.ByteArrayOutputStream;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.ws.Provider;
import javax.xml.ws.Service;
import javax.xml.ws.ServiceMode;
import javax.xml.ws.WebServiceProvider;

@ServiceMode(value=Service.Mode.PAYLOAD)
@WebServiceProvider()
public class SoapProvider implements Provider<Source>
{
    public Source invoke(Source msg)
    {
        StreamResult sr = new StreamResult();

        ByteArrayOutputStream out = new ByteArrayOutputStream();
        sr.setOutputStream(out);

        try {
            Transformer trans = TransformerFactory.newInstance().newTransformer();
            trans.transform(msg, sr);

            // Use out to your heart's desire.
        }
        catch (TransformerException e) {
            e.printStackTrace();
        }    

        return msg;
    }
}

I've ended up not needing this solution, so I haven't actually tried this code myself - it might need some tweaking to get right. But I know this is the right path to go down to get the raw XML from a web service.

(I'm not sure how to make this work if you absolutely must have a SOAPMessage object, but then again, if you're going to be handling the raw XML anyways, why would you use a higher-level object?)

A `StringWriter` is a good alternative to the `ByteArrayOutputStream`+`StreamResult` combination, if you want the XML as a `String` with the correct encoding — artbristol, Nov 20 '13 at 08:51

score 10 · Answer 5 · answered Jun 22 '16 at 20:10

Using Transformer Factory:-

public static String printSoapMessage(final SOAPMessage soapMessage) throws TransformerFactoryConfigurationError,
            TransformerConfigurationException, SOAPException, TransformerException
    {
        final TransformerFactory transformerFactory = TransformerFactory.newInstance();
        final Transformer transformer = transformerFactory.newTransformer();

        // Format it
        transformer.setOutputProperty(OutputKeys.INDENT, "yes");
        transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "2");

        final Source soapContent = soapMessage.getSOAPPart().getContent();

        final ByteArrayOutputStream streamOut = new ByteArrayOutputStream();
        final StreamResult result = new StreamResult(streamOut);
        transformer.transform(soapContent, result);

        return streamOut.toString();
    }

score 7 · Answer 6 · edited Dec 04 '10 at 16:52

7

If you need formatting the xml string to xml, try this:

String xmlStr = "your-xml-string";
Source xmlInput = new StreamSource(new StringReader(xmlStr));
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "2");
transformer.transform(xmlInput,
        new StreamResult(new FileOutputStream("response.xml")));

edited Dec 04 '10 at 16:52

Michael Myers

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answered Dec 04 '10 at 16:28

Hari

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Is it possible to choose between spaces and tabs to do this formatting? BTW, I know tabs are not indicated. – Philippe Gioseffi Jun 22 '18 at 00:05

score 3 · Answer 7 · edited Apr 13 '17 at 14:32

3

this works

 final StringWriter sw = new StringWriter();

try {
    TransformerFactory.newInstance().newTransformer().transform(
        new DOMSource(soapResponse.getSOAPPart()),
        new StreamResult(sw));
} catch (TransformerException e) {
    throw new RuntimeException(e);
}
System.out.println(sw.toString());
return sw.toString();

edited Apr 13 '17 at 14:32

sygi

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answered Apr 13 '17 at 12:32

user2900572

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No explanation needed. – Martin Kersten Jan 19 '18 at 11:29

score 0 · Answer 8 · answered Jun 17 '16 at 15:20

if you have the client code then you just need to add the following two lines to get the XML request/response. Here _call is org.apache.axis.client.Call

String request = _call.getMessageContext().getRequestMessage().getSOAPPartAsString();
String response = _call.getMessageContext().getResponseMessage().getSOAPPartAsString();

score 0 · Answer 9 · answered Aug 13 '19 at 17:37

It is pretty old thread but recently i had a similar issue. I was calling a downstream soap service, from a rest service, and I needed to return the xml response coming from the downstream server as is.

So, i ended up adding a SoapMessageContext handler to get the XML response. Then i injected the response xml into servlet context as an attribute.

public boolean handleMessage(SOAPMessageContext context) {

            // Get xml response
            try {

                ServletContext servletContext =
                        ((ServletRequestAttributes) RequestContextHolder.getRequestAttributes()).getRequest().getServletContext();

                SOAPMessage msg = context.getMessage();

                ByteArrayOutputStream out = new ByteArrayOutputStream();
                msg.writeTo(out);
                String strMsg = new String(out.toByteArray());

                servletContext.setAttribute("responseXml", strMsg);

                return true;
            } catch (Exception e) {
                return false;
            }
        }

Then I have retrieved the xml response string in the service layer.

ServletContext servletContext =
                ((ServletRequestAttributes) RequestContextHolder.getRequestAttributes()).getRequest().getServletContext();

        String msg = (String) servletContext.getAttribute("responseXml");

Didn't have chance to test it yet but this approach must be thread safe since it is using the servlet context.

Getting Raw XML From SOAPMessage in Java

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