How to format a String/char to it's hex value correct

Question

I am trying to convert a String to it's hex representation. I have the following (test) input �¾��Hello World!

The correct hex representation should be: 00 BE 00 00 48 65 6C 6C 6F 20 57 6F 72 6C 64 21

I am trying to format the String with String.format("%x", new BigInteger(toConvert.getBytes("ISO-8859-1"))).split("(?<=\\G.{2})");

But this format operation ignores the first character (if it is a hex-null) and leads to BE 00 00 48 65 6C 6C 6F 20 57 6F 72 6C 64 21

I have already played around a little bit with the parts around the "%x" but nothing helped.

But I am sure, that you can help me :)

Java’s String class is fundamentally not binary safe; any operations on non-printable bytes (like `00`) cannot be expected to work. — Govind Parmar, Sep 09 '18 at 18:03

score 0 · Answer 1 · answered Sep 09 '18 at 19:08

0

To format with leading zeroes, specify the width of the formatted hex value, and request leading zeroes.

E.g. if result is 6 bytes, instead of format "%x", use format "%012x".

For your code, do this: "%0" + toConvert.length() * 2 + "x"

answered Sep 09 '18 at 19:08

Andreas

1 Answers1